Optimal. Leaf size=247 \[ \frac{2 \left (42 a^2 b^2+21 a^4+5 b^4\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{21 d}+\frac{2 b^2 \left (39 a^2+5 b^2\right ) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{21 d}+\frac{8 a b \left (5 a^2+3 b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}-\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{36 a b^3 \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x)}{35 d}+\frac{2 b^2 \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2}{7 d} \]
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Rubi [A] time = 0.365986, antiderivative size = 247, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.348, Rules used = {3842, 4076, 4047, 3768, 3771, 2639, 4046, 2641} \[ \frac{2 b^2 \left (39 a^2+5 b^2\right ) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{21 d}+\frac{8 a b \left (5 a^2+3 b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{5 d}+\frac{2 \left (42 a^2 b^2+21 a^4+5 b^4\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}-\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{36 a b^3 \sin (c+d x) \sec ^{\frac{5}{2}}(c+d x)}{35 d}+\frac{2 b^2 \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2}{7 d} \]
Antiderivative was successfully verified.
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Rule 3842
Rule 4076
Rule 4047
Rule 3768
Rule 3771
Rule 2639
Rule 4046
Rule 2641
Rubi steps
\begin{align*} \int \sqrt{\sec (c+d x)} (a+b \sec (c+d x))^4 \, dx &=\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}+\frac{2}{7} \int \sqrt{\sec (c+d x)} (a+b \sec (c+d x)) \left (\frac{1}{2} a \left (7 a^2+b^2\right )+\frac{1}{2} b \left (21 a^2+5 b^2\right ) \sec (c+d x)+9 a b^2 \sec ^2(c+d x)\right ) \, dx\\ &=\frac{36 a b^3 \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}+\frac{4}{35} \int \sqrt{\sec (c+d x)} \left (\frac{5}{4} a^2 \left (7 a^2+b^2\right )+7 a b \left (5 a^2+3 b^2\right ) \sec (c+d x)+\frac{5}{4} b^2 \left (39 a^2+5 b^2\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{36 a b^3 \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}+\frac{4}{35} \int \sqrt{\sec (c+d x)} \left (\frac{5}{4} a^2 \left (7 a^2+b^2\right )+\frac{5}{4} b^2 \left (39 a^2+5 b^2\right ) \sec ^2(c+d x)\right ) \, dx+\frac{1}{5} \left (4 a b \left (5 a^2+3 b^2\right )\right ) \int \sec ^{\frac{3}{2}}(c+d x) \, dx\\ &=\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 b^2 \left (39 a^2+5 b^2\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{36 a b^3 \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}-\frac{1}{5} \left (4 a b \left (5 a^2+3 b^2\right )\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx+\frac{1}{21} \left (21 a^4+42 a^2 b^2+5 b^4\right ) \int \sqrt{\sec (c+d x)} \, dx\\ &=\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 b^2 \left (39 a^2+5 b^2\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{36 a b^3 \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}-\frac{1}{5} \left (4 a b \left (5 a^2+3 b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx+\frac{1}{21} \left (\left (21 a^4+42 a^2 b^2+5 b^4\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=-\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{5 d}+\frac{2 \left (21 a^4+42 a^2 b^2+5 b^4\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{21 d}+\frac{8 a b \left (5 a^2+3 b^2\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{5 d}+\frac{2 b^2 \left (39 a^2+5 b^2\right ) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{21 d}+\frac{36 a b^3 \sec ^{\frac{5}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b^2 \sec ^{\frac{3}{2}}(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{7 d}\\ \end{align*}
Mathematica [A] time = 1.53072, size = 168, normalized size = 0.68 \[ \frac{2 \sec ^{\frac{7}{2}}(c+d x) \left (5 \left (42 a^2 b^2+21 a^4+5 b^4\right ) \cos ^{\frac{7}{2}}(c+d x) \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )+b \sin (c+d x) \left (5 b \left (42 a^2+5 b^2\right ) \cos ^2(c+d x)+84 a \left (5 a^2+3 b^2\right ) \cos ^3(c+d x)+15 b^3\right )-84 a b \left (5 a^2+3 b^2\right ) \cos ^{\frac{7}{2}}(c+d x) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+42 a b^3 \sin (2 (c+d x))\right )}{105 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 5.392, size = 925, normalized size = 3.7 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b^{4} \sec \left (d x + c\right )^{4} + 4 \, a b^{3} \sec \left (d x + c\right )^{3} + 6 \, a^{2} b^{2} \sec \left (d x + c\right )^{2} + 4 \, a^{3} b \sec \left (d x + c\right ) + a^{4}\right )} \sqrt{\sec \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sec \left (d x + c\right ) + a\right )}^{4} \sqrt{\sec \left (d x + c\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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